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An old riddle I enjoy.


gohan8484

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This one I knew. The answer is envelope. Though I can't agree with it. Can't I just put multiple amount of letters inside an envelope?

Here's another riddle:

A house of wood in a hidden place

Built without nails or glue

High above the earthen ground

It holds pale gems of blue.

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This one I knew. The answer is envelope. Though I can't agree with it. Can't I just put multiple amount of letters inside an envelope?

Here's another riddle:

A house of wood in a hidden place

Built without nails or glue

High above the earthen ground

It holds pale gems of blue.

is it....a nest? I mean, twigs and stuff woven in a tree, and a lot of bird's eggs are blue in colour...

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Its a birds nest. Although that riddle is also slightly wrong, some birds will use mud like glue to hold the nest together.

One of one. Eight of two. One of three. Three of four. One of five. Six of six. Two of seven. Four of eight.

There is a Warrior,

Where is a sword?

Peace did he bring,

The fighting Lord.

Shed for him is my fifth tear.

Find it the title here,

Written in but a single word,

An eye is an eye, until it is heard.

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Its a birds nest. Although that riddle is also slightly wrong, some birds will use mud like glue to hold the nest together.

One of one. Eight of two. One of three. Three of four. One of five. Six of six. Two of seven. Four of eight.

There is a Warrior,

Where is a sword?

Peace did he bring,

The fighting Lord.

Shed for him is my fifth tear.

Find it the title here,

Written in but a single word,

An eye is an eye, until it is heard.

seriously lemming? mud is mud, no matter the use, so it is still correct the riddle.

I do believe the code means that we get TAPESTRY out of the "riddle" at the bottom. Number of letter to number of line. Quite simple. Especially since I've read the pearls of lutra...lol

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FIGURE OUT THE CODE AND SOLVE THE RIDDLES:

1. What did the frog order at McDonald's?

GSFODI GSJFT BOE EJFU DSPBL

2. Why did the banana go to the doctor?

CFDBVTF JU XBT OPU QFFMJOH WFSZ XFMM

3. Why do chickens lay eggs?

JG UIFZ ESPQ UIFN UIFZ CSFBL

First of all these aren't riddles. These are codes practiced by Cryptographers as basics. Anyway here's the answers

1. French Fries and Diet Croak

2. Because it was not peeling very well.

3. If they drop them they break.

I was only able to solve them because I read about such codes in "Digital Fortress" . Try avoiding them or I will counter with much advanced codes.

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@Leviathan, I thought about starting with an easy one but since u know about these codes, it would be pointless to add any more.

Anyways, here's another riddle:

You and your wife organize a dinner party. You invite four other husband-wife couples. You and your wife don't necessarily know everyone you invited. Once everyone is at the party, the people who don't know each other yet shake hands with each other. You can assume that everyone knows their own wife/husband, and that no one shakes their own hand.

After this happens, you ask each person, except for yourself, how many people they shook hands with. Everybody tells you a different number.

How many people did your wife shake hands with?

It actually took me over an hour's thinking to get this. So, please tell me how much time it took u guys if u can answer?

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OK I will say at least this. THIS IS THE TOUGHEST RIDDLE I HAVE EVER FACED OF WITH. OH MAN, MY HEAD HURTS SO MUCH. Anyway........I just solved the riddle and it took me 50 minutes to think it over. Here's the answer....it's 4. Here, I will explain it to u too.

It's given that every person shook hands with different number of people. That means at max one could've shaked with 8 people(Except himself and his wife). But that would also mean that there had to be someone who shook hands with no one. Let's call this person X. If I am correct(i believe I am) Only the spouse of the person who shook hands with 8 people could be person X. Now based on this principle I can also say that the spouse of the person who shook hands with 7 people, shook hands with 1 person. Now if I go on using this principle I will see that the host's wife shook hands with 4 people.

I know my explanation is a bit crappy, but that's the best I can do now(my head hurts and I need to sleep). I will explain everything more clearly tomorrow (if u demand it and I beg u please don't).

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You are absolutely correct. And if your time is 50 minutes, then I guess that makes u smarter than me coz it took me like 68 minutes to figure it out.

Thanks. And I ain't smarter than u. The fact is u told me that u solved it in a little over an hour. That's all I needed. I knew that this riddle, though looked absolutely hard, could be solved with the limited knowledge we had gained up until now. So I just needed to use my brains to it's fullest extent from the very beginning and I had the answer in no time.

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Here's another riddle for u guys:

You have two ropes of equal lengths. Each rope has the property that if you light it on fire at one end, it will take exactly 60 minutes to burn to the other end. Note that the ropes will not burn at a consistent speed the entire time (for example, it's possible that the first 90% of a rope will burn in 1 minute, and the last 10% will take the additional 59 minutes to burn).

Given these two ropes and a matchbook, can you find a way to measure out exactly 45 minutes?

This is a very easy one. So I think most of u can answer it within a minute.

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Ok here, I think I solved it now.To tell you the truth this riddle was harder than your previous one. It took me more than an hour to solve this for God's sake. Here it is:

I solved this problem taking that both the ropes are of the same material and of the same length. Now let A and B be the ends of Rope X and C and D be the ends of the Rope Y. Now it's given, that it would take exactly one hour for a fire to burn a rope completely if the fire was lit at one end.So let's say I light both A and B ends of Rope X at the same time. Then Rope X will be completely burnt in 30 minutes(half of 1 hour). Now while I light Rope X on fire, I will also light up end C of Rope Y. Then while Rope X is completely burnt in 30 minutes, only half of Rope Y will be burnt. That means Rope Y will keep on burning for another 30 minutes. But as soon as the Rope X is completely burnt I will also light up end D of Rope Y. Then Rope Y will completely be burnt in 15 minutes(half of the remaining 30 minutes). So then, I get: 30 minutes (time for burning of Rope X) + 15 minutes (time for burning of half of Rope Y) = 45 minutes.

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If you have me, you want to tell me.

If you tell me, you don’t have me.

The answer is "Secret". Come on Lemming, try solving these brainteasers once in a while instead of the traditional riddles we always see.

Here's another riddle( or rather puzzle). People who play Chess really good will find it much more easier than those who can't.

Here it is:

In chess, queens can move horizontally, vertically, or diagonally, as far as they like, as shown in the picture. We say that a queen can "attack" another piece if it can move into the other piece on the next move. How can you place 8 queens on a chessboard such that none of the queens can attack each other?

Here I will even give an image for your help:

EmptyBoard.gif

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